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45x^2-29x=30
We move all terms to the left:
45x^2-29x-(30)=0
a = 45; b = -29; c = -30;
Δ = b2-4ac
Δ = -292-4·45·(-30)
Δ = 6241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6241}=79$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-79}{2*45}=\frac{-50}{90} =-5/9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+79}{2*45}=\frac{108}{90} =1+1/5 $
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